A metal wire of diameter 1 mm, is held on two knife edges separated by a distance of 50 cm. The tension in the wire is 100 N. The wire vibrating in its fundamental frequency and a vibrating tuning fork together produces 5 beats per sec. The tension in the wire is then reduced to 81 N. When the two are excited, beats are again at the same rate. Calculate
Text Solution
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[ 95 Hz, 
kg/m 3 ]
– n = 5..........(1)
n – 
= 5 .........(2)
add equ (1) and (2)
= 10
= 
= 
= 
(µ = 0.01)
ρ πr 2 = 0.01
ρ = 
= 
= 
× 10 3 kg/m 3
put µ = 0.01 in eq. (1)
– n = 5
n = 100 – 5 = 95 Hz
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